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Description
Can you solve it?
Source
not provided yet
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you are a faggot
I didn’t know what to put in and went with the
“wow all this work for ‘you are a faggot’? >.>”
approach xD
DING DING DING! We have a winner!
I like how you deciphered it :)
It is a Polybius cipher .
I brought in the six because when I made this riddle I didn’t know that something like this already existed, let alone know it’s name. Another friend pointed out that this is a Polybius, albeit a irregular one. Hence my hint with the 6 and “I was pragmatic”^^.
Kudos to you TLATopHat :)
Pattern:
1 A B C D E
2 F G H I J
3 K L M N O
4 P Q R S T
5 U V W X Y
6 Z
row first column later.
… WHAT WAS THE POINT OF THAT MESSAGE?!?
If each pair of digits is a letter, we have:
_ _ _ / _ _ _ / _ / _ _ _ _ _ _
A letter on its own is usually “A” or “I”, so I assumed “11”=“A”:
_ _ _ / A _ _ / A / _ A _ _ _ _
I then assumed 15 would correspond to the 4th letter after “A”, which is “E”:
_ _ _ / A _ E / A / _ A _ _ _ _
Which led me to guess that R = 43:
_ _ _ / A R E / A / _ A _ _ _ _
The only 3-letter personal pronoun that can be followed by the word “ARE” is “YOU”, giving us Y=55, O=35, U=51:
Y O U / A R E / A / _ A _ _ O _
By this point I had a makeshift spread sheet, and I spotted the pattern. The letters were numbers in groups of five from A-Z like so: 11-15, 21-25, 31-35, 41-45, 51-55, and 61=Z (which matches your hint that it was possible to have a “6”)
With the cipher solved, we now know that 21=F, 22=G, and 45=T:
Y O U / A R E / A / F A G G O T
Second: each group has an even number of digits.
Third: the digits range from 1-5.
Finally: there is a word with a single letter.
553551 114315 11 211122223545
55 35 51 | 11 43 15 | 11 | 21 11 22 22 35 45
30 20 26 | 6 23 10 | 6 | 11 6 12 12 20 25
25 15 21 | 1 18 5 | 1 | 6 1 7 7 15 20
I’ll let you do the final step so you can have the pleasure of discovering on your own.
I was pragmatic.
Added together: 71
Mean: 17.75
Multiplied: 21600
Alright, can I have a hint?
No
Eeceea kdco
k vkwwcede
Is that it?